Exercise 11.1 — Monomial x Monomial

Problems based on multiplying a monomial by another monomial.

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What is Exercise 11.1 About?

Exercise 11.1 of Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus) focuses on the multiplication of algebraic monomials. A monomial is a single-term algebraic expression such as 6, 7k, -3l, or 5x²y. When you multiply two or more monomials, you multiply their coefficients (numbers) separately and their variable parts separately using the laws of exponents.

This exercise contains seven types of problems: multiplying pairs of monomials, completing a multiplication table, finding volumes of rectangular boxes, multiplying multiple monomials, evaluating expressions with substitution, and creating your own monomials. All of these build the foundation needed for polynomial multiplication in Class 9 and 10.

Monomials Coefficients Laws of Exponents Product of Variables Volume = l × b × h
💡 Golden Rule: To multiply monomials — multiply coefficients together, then multiply variable parts together using the rule xᵃ × xᵇ = xᵃ⁺ᵇ.

Question 1 — Multiplying Pairs of Monomials

Each sub-question asks you to find the product of two monomials. The method is always the same: group the numbers and group the variables, then simplify each group.

Part (i)
Find the product of 6 and 7k
6 × 7k = (6 × 7) × (k) ← group numbers, group variables = 42 × k = 42k

Since 6 is a plain number (no variable), we simply multiply 6 × 7 = 42 and attach the variable k.

Part (ii)
Find the product of −3l and −2m
(−3l) × (−2m) = (−3 × −2) × (l × m) ← negative × negative = positive = 6 × lm = 6lm

Sign rule reminder: Negative × Negative = Positive. So (−3) × (−2) = +6.

Part (iii)
Find the product of −5t² and −3t²
(−5t²) × (−3t²) = (−5 × −3) × (t² × t²) = 15 × t2+2 ← add exponents: xᵃ × xᵇ = xᵃ⁺ᵇ = 15t⁴
t² × t² = t²⁺² = t⁴
Part (iv)
6n × 3m
= (6 × 3) × (n × m) = 18 × nm
18mn
Part (v)
−5p² × −2p
= (−5 × −2) × (p² × p) = 10 × p²⁺¹ = 10p³
10p³
Pattern to remember: Multiply coefficients → add exponents of same variables → write the simplified monomial. This three-step pattern works for every monomial multiplication.

Question 2 — Complete the Multiplication Table

This problem gives a large multiplication table with row and column headers as monomials. Each cell contains the product of the row-header monomial and the column-header monomial. Two sample cells are pre-filled to guide you (e.g., 3x × 5x = 15x²; −2x² × 5x = −10x³). The table below shows the complete, filled version.

📌 How to use this table: Pick any row monomial and any column monomial, multiply them using the monomial rule, and write the result in the cell. Check sign carefully — a negative row × positive column = negative product.
× 5x −2y² 3x² 6xy 3y² −3xy² 4xy² x²y²
3x 15x² −6xy² 9x³ 18x²y 9xy² −9x²y² 12x²y² 3x³y²
4y 20xy −8y³ 12x²y 24xy² 12y³ −12xy³ 16xy³ 4x²y³
−2x² −10x³ 4x²y² −6x⁴ −12x³y −6x²y² 6x³y² −8x³y² −2x⁴y²
6xy 30x²y −12xy³ 18x³y 36x²y² 18xy³ −18x²y³ 24x²y³ 6x³y³
2y² 10xy² −4y⁴ 6x²y² 12xy³ 6y⁴ −6xy⁴ 8xy⁴ 2x²y⁴
3x²y 15x³y −6x²y³ 9x⁴y 18x³y² 9x²y³ −9x³y³ 12x³y³ 3x⁴y³
2xy² 10x²y² −4xy⁴ 6x³y² 12x²y³ 6xy⁴ −6x²y⁴ 8x²y⁴ 2x³y⁴
5x²y² 25x³y² −10x²y⁴ 15x⁴y² 30x³y³ 15x²y⁴ −15x³y⁴ 20x³y⁴ 5x⁴y⁴
🟡 Highlighted cells were pre-filled in the textbook question as examples. All other cells (in green) are the answers you need to fill in. Use the row-header monomial × column-header monomial pattern for every cell.
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Question 3 — Volume of Rectangular Boxes

The volume of a rectangular box (cuboid) is calculated using the formula V = l × b × h. When the dimensions are given as algebraic monomials, you simply multiply all three monomials together. This question tests your ability to apply monomial multiplication in a real-world geometric context.

Volume (V) = Length (l) × Breadth (b) × Height (h)
S.No. Length (l) Breadth (b) Height (h) Volume = l × b × h
(i) 3x 4x² 5 3x × 4x² × 5 = 60x³
(ii) 3a² 4 5c 3a² × 4 × 5c = 60a²c
(iii) 3m 4n 2m² 3m × 4n × 2m² = 24m³n
(iv) 6kl 3l² 2k² 6kl × 3l² × 2k² = 36k³l³
(v) 3pr 2qr 4pq 3pr × 2qr × 4pq = 24p²q²r²

Let's trace through problem (iv) in detail so the method is clear:

6kl × 3l² × 2k² = (6 × 3 × 2) × (k × k²) × (l × l²) ← group numbers, group each variable = 36 × k¹⁺² × l¹⁺² = 36k³l³
Tip: When multiplying three monomials for volume, group ALL the numbers together first and ALL instances of each variable together. Then add exponents for each variable group.

Question 4 — Products of Multiple Monomials

Here, you multiply three or more monomials at once. The principle is the same — but you need to be careful to collect all coefficients and all powers of each variable correctly.

Part (i)
Find the product of: xy, x²y, xy, x
xy × x²y × xy × x = (x × x² × x × x) × (y × y × y) ← group x's and y's = x1+2+1+1 × y1+1+1 = x⁵ × y³ = x⁵y³
Part (ii)
Find the product of: a, b, ab, a³b, ab³
a × b × ab × a³b × ab³ = (a × a × a³ × a) × (b × b × b × b³) = a1+1+3+1 × b1+1+1+3 = a⁶ × b⁶ = a⁶b⁶
Part (iii)
kl × lm × km × klm
= k1+1+1 × l1+1+1 × m1+1+1 = k³ × l³ × m³
k³l³m³
Part (iv)
pq × pqr × r
= p1+1 × q1+1 × r1+1 = p² × q² × r²
p²q²r²
Part (v)
Find the product of: −3a, 4ab, −6c, d
(−3a) × 4ab × (−6c) × d = (−3 × 4 × −6) × (a × a) × (b) × (c) × (d) = (+72) × a² × b × c × d ← (−) × (+) × (−) = positive = 72a²bcd
⚠️ Sign check: (−3) × 4 = −12  →  (−12) × (−6) = +72. Always track signs step by step.

Questions 5 & 6 — Evaluate Expressions by Substitution

These questions assign algebraic expressions to variables and ask you to calculate the value of a combined expression. You first find the product of the assigned expressions, then simplify.

Question 5
If A = xy, B = yz and C = zx, find ABC
ABC = xy × yz × zx = (x × x) × (y × y) × (z × z) = x² × y² × z² = x²y²z²
Question 6
If P = 4x², T = 5x and R = 5y, find PTR ÷ 100
PTR = 4x² × 5x × 5y = (4 × 5 × 5) × x² × x × y = 100 × x³y = 100x³y   PTR ÷ 100 = 100x³y ÷ 100 = x³y
📌 The division by 100 neatly cancels the coefficient, leaving just x³y. This type of question tests whether you can handle both multiplication and division of monomials in the same problem.

Question 7 — Create Your Own Monomials and Multiply

This open-ended question encourages you to explore monomial multiplication on your own. You pick any monomials you like, then find their product. The textbook uses 2a, 3a²b, −4b³ as an example:

2a × 3a²b × (−4b³) = (2 × 3 × −4) × (a × a²) × (b × b³) = −24 × a³ × b⁴ = −24a³b⁴

You can try monomials involving three or more variables, or choose all-positive terms for practice. The key is to demonstrate that you can correctly group and add exponents for each variable.

💡 Try these combinations yourself:
  • 5x, 2x²y, 3y² → product = 30x³y³
  • −2p², 3pq, −q² → product = 6p³q³
  • 4ab, 2bc, 3ca → product = 24a²b²c²

Common Mistakes to Avoid

  • Forgetting to add exponents: When multiplying x² × x³, students sometimes write x⁶ (multiplied) instead of the correct x⁵ (added). Always add exponents for the same base.
  • Sign errors with negatives: Two negatives multiply to a positive. Three negatives multiply to a negative. Count the number of negative signs before assigning the final sign.
  • Mixing up different variables: In a product like x²y × xy², keep x-powers and y-powers separate. Result: x²⁺¹ × y¹⁺² = x³y³.
  • Leaving coefficients out: When copying a monomial, students sometimes write only the variable part and drop the number coefficient. Always multiply all the number parts together.
  • Confusing addition and multiplication rules: In addition, you can only combine like terms (e.g., 3x + 2x = 5x). In multiplication, unlike terms are fine — 3x × 2y = 6xy.
Most common board exam error: Writing x² × x³ = x⁶ instead of x⁵. Exponents are added, not multiplied. This mistake alone can cost you 1–2 marks per question.

Quick Reference — All Answers at a Glance

QuestionExpressionAnswer
Q1(i)6 × 7k42k
Q1(ii)−3l × −2m6lm
Q1(iii)−5t² × −3t²15t⁴
Q1(iv)6n × 3m18mn
Q1(v)−5p² × −2p10p³
Q3(i)3x × 4x² × 560x³
Q3(ii)3a² × 4 × 5c60a²c
Q3(iii)3m × 4n × 2m²24m³n
Q3(iv)6kl × 3l² × 2k²36k³l³
Q3(v)3pr × 2qr × 4pq24p²q²r²
Q4(i)xy · x²y · xy · xx⁵y³
Q4(ii)a · b · ab · a³b · ab³a⁶b⁶
Q4(iii)kl · lm · km · klmk³l³m³
Q4(iv)pq · pqr · rp²q²r²
Q4(v)−3a × 4ab × −6c × d72a²bcd
Q5ABC = xy · yz · zxx²y²z²
Q6PTR/100x³y

What This Exercise Prepares You For

Fluency in multiplying monomials is the essential building block for the rest of Chapter 11. The next section on multiplying a monomial by a polynomial (Exercise 11.2) extends this exact skill — instead of single terms, you distribute the monomial across each term in a bracket.

These skills also reappear directly in Chapter 12 — Factorisation, where you reverse the process: splitting a product back into its factors. In Class 9 and 10, monomial multiplication is the engine behind expanding brackets in polynomial expressions and verifying identities in algebra.

For Telangana and Andhra Pradesh board exams, Exercise 11.1 type questions regularly appear as 1-mark or 2-mark fill-in-the-table problems. Mastering the product table format (Question 2) gives you a significant advantage.

📐 Board Exam Tip (Telangana & AP): For Question 2 (the product table), write out each multiplication step in the margin — even if the table cell only needs the answer. Showing working helps you earn partial marks if the final answer has a sign error.
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