Chapter 14.1 — Introduction to Surface Areas
Introduction of surface areas of cube and cuboid. This is Lesson 1 of 3 in Chapter 14: Surface Area and Volume (Cube-Cuboid).
Unfolding a Cuboid Into Six Flat Rectangles
A cuboid has six faces, and the fastest way to see why its surface area formula looks the way it does is to imagine peeling all six faces off and laying them flat, still attached where they used to share an edge — essentially the same "net" idea already used to describe how a cube unfolds, applied now to work out an actual area rather than just to identify a shape.
Three Matching Pairs of Rectangles
Every cuboid's six faces come in three matching pairs — two faces of length × height (l × h), two of breadth × height (b × h), and two of length × breadth (l × b), with each pair sitting on opposite sides of the solid:
Six is always the right number of faces to expect, and three is always the right number of matching pairs — a cuboid never has, say, five faces or four differently-sized pairs, since opposite faces of a cuboid are always congruent to each other by construction.
Adding up all six flattened rectangles gives the total surface area directly, one pair at a time:
T.S.A. of a cuboid = lh + bh + lh + bh + lb + lb
= 2lh + 2bh + 2lb = 2(lh + bh + lb)Nothing about this formula needs memorising as an isolated fact — it's simply "add up six rectangles," grouped into the three matching pairs that any cuboid always has.
A Worked Check Against a Concrete Cuboid
Substituting real numbers confirms the formula behaves as expected. Take a cuboid measuring 5 units × 3 units × 2 units (l=5, b=3, h=2):
T.S.A. = 2(lh + bh + lb) = 2(5×2 + 3×2 + 5×3) = 2(10 + 6 + 15) = 2(31) = 62 sq. unitsChecking this against the six individual faces directly: two 5×2 faces (10 sq. units each, 20 total), two 3×2 faces (6 sq. units each, 12 total), and two 5×3 faces (15 sq. units each, 30 total). Adding those three totals — 20+12+30 — gives 62, exactly matching the formula's result, confirming the grouped formula is just a faster way of adding the same six numbers, not a shortcut that skips over any of them. This kind of direct check — computing the six faces individually and comparing the total against the compact formula — is worth doing at least once for any new shape's surface-area formula, since it's the fastest way to confirm a formula has actually been remembered correctly before relying on it for a genuinely new problem.
Leaving the Top and Bottom Uncounted
Sometimes only the four "standing" side faces matter — painting the outside walls of a room, for instance, never touches the ceiling or floor, and wrapping a label around a rectangular box never covers its top or bottom either. Removing the two l×b faces (the top and bottom) from the six-face total leaves only the four side faces:
Lateral surface area of a cuboid = lh + bh + lh + bh = 2lh + 2bh = 2h(l + b)The relationship between the two formulas is direct: total surface area is the lateral surface area plus the two l×b faces that lateral surface area deliberately leaves out — T.S.A. = L.S.A. + 2lb, always. For the same 5×3×2 cuboid checked above, L.S.A. = 2h(l+b) = 2×2×(5+3) = 4×8 = 32 sq. units, and adding back the two missing l×b faces (2×15=30) gives 32+30=62 — exactly the T.S.A. found earlier, confirming the two formulas fit together consistently rather than being two unrelated facts about the same solid.
Every Face Is Still Just a Rectangle
It's worth being explicit about what makes this chapter's formulas so approachable: every single face of a cuboid, without exception, is a plain rectangle, and finding a rectangle's area — length times breadth — was already covered in full back in the chapter on areas of plane figures. Nothing about a 3-D solid's surface area needs a genuinely new area formula; it only needs the skill of identifying how many rectangles make up the solid's outside, and which pairs of them happen to be the same size. A cylinder or a cone, by contrast, would need a curved-surface formula that isn't just "length times breadth" — which is exactly why this chapter restricts itself to cubes and cuboids, the two solids whose entire surface is built from flat rectangles alone.
The Cube Version of Both Formulas
A cube is simply a cuboid where length, breadth, and height are all equal to the same value, l — the same relationship already familiar from the areas chapter, where a square was described as a rectangle with equal length and breadth. Substituting b = h = l into both formulas above collapses each one down to a single term. Since every one of a cube's six faces is now an identical l×l square:
Total surface area of a cube = l² + l² + l² + l² + l² + l² = 6l²
Lateral surface area of a cube = l² + l² + l² + l² = 4l²The cube's lateral surface area uses only four of its six faces — the same "leave out the top and bottom" idea as the cuboid, just with every face now the same size, so the four side faces simply become 4l² rather than a sum of two different rectangle types.
Checking the Two Formulas Agree Where They Should
Since a cube is a special case of a cuboid, its two surface-area formulas should agree with the cuboid formulas once l=b=h is substituted in. Checking total surface area: 2(lh+bh+lb) with b=h=l becomes 2(l·l+l·l+l·l) = 2(3l²) = 6l², matching 6l² exactly. Checking lateral surface area: 2h(l+b) with b=h=l becomes 2l(l+l) = 2l(2l) = 4l², matching 4l² exactly. Both cube formulas are genuinely just the cuboid formulas with a repeated variable, not separate rules invented from scratch. This is worth trusting as a general pattern: whenever a cube-specific formula in this chapter looks unfamiliar, substituting b=h=l into the equivalent cuboid formula will always reproduce it, since a cube never needed its own separate geometry in the first place — only a cuboid whose three dimensions happen to coincide, the same way a square is never anything more than a rectangle that happens to have matching sides.
What Comes Next
These four formulas — cuboid T.S.A., cuboid L.S.A., cube T.S.A., cube L.S.A. — are put to direct use in Exercise 14.1, including comparing how much material two different boxes need and costing out a painting job. Exercise 14.2 then moves from surface (how much material covers a solid) to volume (how much space it fills) — a genuinely different question, even though it's asked about the very same shapes — surface area answers "how much wrapping paper," while volume answers "how much fits inside," and a solid can score high on one measure while scoring low on the other.