Exercise 5.1 — Basic Applications

Simple applications of ratio, proportion and percentage.

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Exercise 5.1 is the first practice exercise of Chapter 5, Comparing Quantities Using Proportion, in Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus). It puts every idea from the chapter's introduction — ratio, compound ratio, and percentage — to work in realistic situations: comparing working hours, mixing liquids of different units, splitting business profits, adjusting supermarket prices, and even a tricky ratio-based geometry problem involving points on a line.

Below is a complete, step-by-step explanation of all 14 problems in this exercise, grouped by theme so the underlying pattern in each type of question is easy to spot and reuse.

Simplifying Ratios Compound Ratio Equations Ratio Word Problems Percentage Applications
💡 Core idea of this exercise: Almost every problem here follows the same three moves — (1) convert both quantities to the same unit if needed, (2) write the comparison as a ratio or percentage statement, and (3) simplify or cross-multiply to find the unknown. Spotting which of these three moves a question needs is the real skill being tested.

Part 1 — Finding and Simplifying Basic Ratios (Q1)

Question: Find the ratio of the following quantities, in simplest form.

Q1 (i)

Smita works 6 hours and Kajal works 8 hours. Find the ratio of their working hours.

Ratio = 6 hours : 8 hours = 6 : 8 Divide both terms by HCF (2): 3 : 4
Q1 (ii)

One pot contains 8 litres of milk, the other contains 750 millilitres. Find the ratio.

Convert to the same unit: 1 litre = 1000 mL → 8 litres = 8000 mL Ratio = 8000 : 750 Divide both terms by HCF (250): 32 : 3
Q1 (iii)

A cycle travels at 15 km/h and a scooter at 30 km/h. Find the ratio of their speeds.

Ratio = 15 : 30 Divide both terms by HCF (15): 1 : 2
Don't skip the unit conversion: Q1(ii) is the classic trap of this section — writing "8 : 750" without converting litres to millilitres first gives a completely meaningless ratio, since the two numbers wouldn't even be measuring the same kind of unit.

Part 2 — Solving for an Unknown in a Compound Ratio (Q2, Q3, Q4)

These three problems all use the compound ratio rule — multiply the antecedents together, and multiply the consequents together — and then solve the resulting simple equation for the unknown.

Q2

The compound ratio of 5 : 8 and 3 : 7 is 45 : x. Find x.

Compound ratio = (5×3) : (8×7) = 15 : 56 So 15 : 56 = 45 : x → cross-multiply: 15x = 56 × 45 x = (56 × 45) / 15 = 56 × 3 = 168
Q3

The compound ratio of 7 : 5 and 8 : x is 84 : 60. Find x.

Compound ratio = (7×8) : (5×x) = 56 : 5x So 56 : 5x = 84 : 60 → cross-multiply: 56 × 60 = 5x × 84 x = (56 × 60) / (5 × 84) = 8/1 = 8
Q4

The compound ratio of 3 : 4 and the inverse ratio of 4 : 5 is 45 : x. Find x.

📌 The inverse ratio of a : b is simply b : a — so the inverse of 4 : 5 is 5 : 4.
Compound ratio = (3×5) : (4×4) = 15 : 16 So 15 : 16 = 45 : x → cross-multiply: 15x = 16 × 45 x = (16 × 45) / 15 = 16 × 3 = 48
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Part 3 — Real-Life Ratio Word Problems (Q5, Q7, Q8)

Q5

A school keeps 3 teachers for every 60 students. If 400 students are enrolled, how many teachers should there be, in the same ratio?

Ratio of teachers to students = 3 : 60 = 1 : 20 Let teachers needed = x → 1 : 20 = x : 400 1 × 400 = 20 × x → x = 400/20 = 20
20 teachers are needed for 400 students, in the same ratio.
Q7

9 out of 24 students scored below 75% marks in a test. Find the ratio of students who scored below 75% to those who scored 75% and above.

Below 75% = 9; total = 24 → 75% and above = 24 − 9 = 15 Ratio = 9 : 15 = (divide by HCF 3) 3 : 5
Q8

Find the ratio of vowels to consonants in the word "MISSISSIPPI", in simplest form.

Vowels in MISSISSIPPI: I, I, I, I → 4 vowels Consonants: M, S, S, S, S, P, P → 7 consonants Ratio of vowels to consonants = 4 : 7  (already in simplest form)

Part 4 — Using Ratios to Compare Triangle Sides (Q6, Q10)

Q6

In the right triangle ABC shown below (with AB = 8 cm, BC = 6 cm, AC = 10 cm), write all six possible ratios by pairing up the sides.

A B C AB = 8 cm BC = 6 cm AC = 10 cm

A right-angled triangle with the classic 6–8–10 (a multiple of the 3–4–5) side ratio.

RatioComputationSimplest Form
AB : BC8 : 64 : 3
BC : AB6 : 83 : 4
BC : AC6 : 103 : 5
AC : BC10 : 65 : 3
AC : AB10 : 85 : 4
AB : AC8 : 104 : 5
Q10

In ΔABC: AB = 2.2 cm, BC = 1.5 cm, AC = 2.3 cm. In ΔXYZ: XY = 4.4 cm, YZ = 3 cm, XZ = 4.6 cm. Find AB : XY, BC : YZ, AC : XZ. Are the corresponding sides in proportion?

B C A ΔABC (small) Y Z X ΔXYZ (twice as large)

ΔXYZ is the same shape as ΔABC, just scaled up — every side of XYZ is exactly double the corresponding side of ABC.

AB : XY = 2.2 : 4.4 = 1 : 2 BC : YZ = 1.5 : 3 = 1 : 2 AC : XZ = 2.3 : 4.6 = 1 : 2
Yes — all three ratios simplify to the same value, 1 : 2, so the corresponding sides of ΔABC and ΔXYZ are in proportion. (This also means the two triangles are similar, with ΔXYZ exactly twice the size of ΔABC.)

Part 5 — Percentage Word Problems (Q9, Q12, Q13)

Q9

Rehana receives 25% of the monthly profit in a business she co-owns with Rajendra. If she received ₹2080 in a month, what was the total profit that month?

Let total profit = x → 25% of x = 2080 (25/100) × x = 2080 → x/4 = 2080 x = 2080 × 4 = 8320
✅ Total profit for the month = ₹8320.
Q12

A club had 2075 members last year. This year, enrolment decreased by 4%. (a) Find the decrease. (b) Find this year's enrolment.

(a) Decrease = 4% of 2075 = (4/100) × 2075 = 8300/100 = 83 (b) This year's enrolment = 2075 − 83 = 1992
Q13

A farmer harvested 1720 bags of cotton last year and expects a 20% increase this year. How many bags does she expect this year?

Expected bags = 1720 × (100+20)/100 = 1720 × 120/100 = 172 × 12 = 2064
✅ She expects 2064 bags of cotton this year.
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Part 6 — Updating a Whole Price Table With Percentage Changes (Q11)

Question: Madhuri visits a supermarket where rice and jam/fruits have gone down in price, while oil and dal have gone up. Find every changed price below.

  • Rice and Jam/Apples (fruits): price decreased by 5% (rice) and 8% (jam & apples)
  • Oil and Dal: price increased by 10%
Worked Solution — Item by Item
Rice: 30 × (100−5)/100 = 30 × 95/100 = 57/2 = ₹28.50 Jam: 100 × (100−8)/100 = 100 × 92/100 = ₹92.00 Apples: 280 × (100−8)/100 = 280 × 92/100 = 1288/5 = ₹257.60 Oil: 120 × (100+10)/100 = 120 × 110/100 = ₹132.00 Dal: 80 × (100+10)/100 = 80 × 110/100 = ₹88.00
ItemOriginal Price% ChangeChanged Price
Rice₹30−5%₹28.50
Jam₹100−8%₹92.00
Apples₹280−8%₹257.60
Oil₹120+10%₹132.00
Dal₹80+10%₹88.00
📌 Notice the pattern: Every single row uses the same formula, x × (100±y)/100 — only the original price and the percentage (and whether it's an increase or decrease) change from row to row. Once you recognise this, a five-item price table is no harder than a single percentage question repeated five times.

Part 7 — A Challenging Ratio-Division Problem on a Line Segment (Q14)

Question: Points P and Q lie on segment AB, on the same side of its midpoint. P divides AB in the ratio 2 : 3, and Q divides AB in the ratio 3 : 4. If PQ = 2, find the length of AB.

A P Q B PQ = 2 AP : PB = 2 : 3 AQ : QB = 3 : 4

Both P and Q sit between A's midpoint and B, with P closer to A than Q — so PB is longer than QB, and PQ = PB − QB.

Worked Solution

The trick is to express both PB and QB as a fraction of the whole length AB, then subtract.

AP : PB = 2 : 3 → AP/PB = 2/3 → add 1 to both sides: (AP+PB)/PB = 5/3 → AB/PB = 5/3 → PB = (3/5)AB  ...(1) AQ : QB = 3 : 4 → AQ/QB = 3/4 → add 1 to both sides: (AQ+QB)/QB = 7/4 → AB/QB = 7/4 → QB = (4/7)AB  ...(2) PQ = PB − QB = (3/5)AB − (4/7)AB = [(21−20)/35]AB = (1/35)AB Given PQ = 2: 2 = (1/35)AB → AB = 35 × 2 = 70
Length of AB = 70 units.
💡 Why "add 1 to both sides" works: Turning AP/PB = 2/3 into (AP+PB)/PB swaps the comparison from "part to part" into "whole to part" — and since AP + PB is exactly AB, this is what lets you express PB as a clean fraction of the total length AB.

Common Mistakes to Avoid

  • Forgetting unit conversion before forming a ratio: As in Q1(ii), litres and millilitres (or any mismatched units) must be converted to the same unit first.
  • Multiplying the wrong terms in a compound ratio: Always multiply antecedent × antecedent and consequent × consequent — never antecedent × consequent.
  • Forgetting to invert a ratio when asked: In Q4, the "inverse ratio of 4 : 5" is 5 : 4, not 4 : 5 — missing this flip changes the entire answer.
  • Mixing up "increased by" and the final new value: Q12 and Q13 ask for the change and the new total separately — always re-read which one the question wants.
  • Assuming PQ = PB + QB instead of PB − QB: In problems like Q14, carefully figure out the actual order of the points on the line before deciding whether to add or subtract two segment lengths.
  • Not double-checking with cross-multiplication: Whenever a ratio equation involves an unknown (like Q2, Q3), cross-multiplying is the safest way to isolate that unknown without sign or fraction errors.
Exam tip: For multi-part percentage questions like Q11, show the formula once clearly, then apply it as a simple substitution for every remaining item — examiners give full credit for a correctly repeated method, and it's much faster than re-deriving the logic for every row.

Quick Reference — All 14 Answers at a Glance

Q.NoScenarioKey Result
1(i)Working hours, 6 hrs & 8 hrs3 : 4
1(ii)Milk, 8 L & 750 mL32 : 3
1(iii)Speeds, 15 km/h & 30 km/h1 : 2
2Compound ratio: 5:8 & 3:7 = 45:xx = 168
3Compound ratio: 7:5 & 8:x = 84:60x = 8
43:4 compound with inverse of 4:5x = 48
5Teachers for 400 students (ratio 3:60)20 teachers
6All 6 side ratios of an 8-6-10 triangle4:3, 3:4, 3:5, 5:3, 5:4, 4:5
7Below/above 75% marks (9 of 24)3 : 5
8Vowels : consonants in "MISSISSIPPI"4 : 7
925% profit share = ₹2080Total profit = ₹8320
10ΔABC vs ΔXYZ side ratiosAll 1:2 — sides are in proportion
115-item supermarket price table₹28.50, ₹92, ₹257.60, ₹132, ₹88
12Club enrolment, 4% decrease from 2075Decrease 83; new total 1992
13Cotton yield, 20% increase from 17202064 bags
14Points P, Q dividing AB; PQ = 2AB = 70 units

What This Exercise Prepares You For

Exercise 5.1 directly applies the formulas from the chapter introduction on ratio, proportion, compound ratio and percentage — if any step above felt unfamiliar, that's the right place to revise the underlying rule before continuing.

The percentage-change skills practised in Q11, Q12, and Q13 carry forward directly into the chapter's next exercises on profit, loss, discount, and simple interest, while the ratio-of-sides idea in Q6 and Q10 is a first taste of triangle similarity, a concept explored in much greater depth in the Triangles chapter in Class 9.

📐 Board Exam Tip (CBSE, Telangana & AP): Word problems like Q5, Q9, and Q13 are graded on correctly setting up the ratio or percentage equation just as much as on the final number — always write out the "let x = ..." statement and the equation explicitly before solving, even if you can do the arithmetic quickly in your head.
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