Exercise 5.1 — Basic Applications
Simple applications of ratio, proportion and percentage.
Exercise 5.1 — Ratio, Compound Ratio & Percentage Word Problems
Class 8 Mathematics · CBSE, Telangana & Andhra Pradesh Syllabus · Chapter 5: Comparing Quantities Using Proportion
Exercise 5.1 is the first practice exercise of Chapter 5, Comparing Quantities Using Proportion, in Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus). It puts every idea from the chapter's introduction — ratio, compound ratio, and percentage — to work in realistic situations: comparing working hours, mixing liquids of different units, splitting business profits, adjusting supermarket prices, and even a tricky ratio-based geometry problem involving points on a line.
Below is a complete, step-by-step explanation of all 14 problems in this exercise, grouped by theme so the underlying pattern in each type of question is easy to spot and reuse.
Part 1 — Finding and Simplifying Basic Ratios (Q1)
Question: Find the ratio of the following quantities, in simplest form.
Smita works 6 hours and Kajal works 8 hours. Find the ratio of their working hours.
One pot contains 8 litres of milk, the other contains 750 millilitres. Find the ratio.
A cycle travels at 15 km/h and a scooter at 30 km/h. Find the ratio of their speeds.
Part 2 — Solving for an Unknown in a Compound Ratio (Q2, Q3, Q4)
These three problems all use the compound ratio rule — multiply the antecedents together, and multiply the consequents together — and then solve the resulting simple equation for the unknown.
The compound ratio of 5 : 8 and 3 : 7 is 45 : x. Find x.
The compound ratio of 7 : 5 and 8 : x is 84 : 60. Find x.
The compound ratio of 3 : 4 and the inverse ratio of 4 : 5 is 45 : x. Find x.
Part 3 — Real-Life Ratio Word Problems (Q5, Q7, Q8)
A school keeps 3 teachers for every 60 students. If 400 students are enrolled, how many teachers should there be, in the same ratio?
9 out of 24 students scored below 75% marks in a test. Find the ratio of students who scored below 75% to those who scored 75% and above.
Find the ratio of vowels to consonants in the word "MISSISSIPPI", in simplest form.
Part 4 — Using Ratios to Compare Triangle Sides (Q6, Q10)
In the right triangle ABC shown below (with AB = 8 cm, BC = 6 cm, AC = 10 cm), write all six possible ratios by pairing up the sides.
A right-angled triangle with the classic 6–8–10 (a multiple of the 3–4–5) side ratio.
| Ratio | Computation | Simplest Form |
|---|---|---|
| AB : BC | 8 : 6 | 4 : 3 |
| BC : AB | 6 : 8 | 3 : 4 |
| BC : AC | 6 : 10 | 3 : 5 |
| AC : BC | 10 : 6 | 5 : 3 |
| AC : AB | 10 : 8 | 5 : 4 |
| AB : AC | 8 : 10 | 4 : 5 |
In ΔABC: AB = 2.2 cm, BC = 1.5 cm, AC = 2.3 cm. In ΔXYZ: XY = 4.4 cm, YZ = 3 cm, XZ = 4.6 cm. Find AB : XY, BC : YZ, AC : XZ. Are the corresponding sides in proportion?
ΔXYZ is the same shape as ΔABC, just scaled up — every side of XYZ is exactly double the corresponding side of ABC.
Part 5 — Percentage Word Problems (Q9, Q12, Q13)
Rehana receives 25% of the monthly profit in a business she co-owns with Rajendra. If she received ₹2080 in a month, what was the total profit that month?
A club had 2075 members last year. This year, enrolment decreased by 4%. (a) Find the decrease. (b) Find this year's enrolment.
A farmer harvested 1720 bags of cotton last year and expects a 20% increase this year. How many bags does she expect this year?
Part 6 — Updating a Whole Price Table With Percentage Changes (Q11)
Question: Madhuri visits a supermarket where rice and jam/fruits have gone down in price, while oil and dal have gone up. Find every changed price below.
- Rice and Jam/Apples (fruits): price decreased by 5% (rice) and 8% (jam & apples)
- Oil and Dal: price increased by 10%
| Item | Original Price | % Change | Changed Price |
|---|---|---|---|
| Rice | ₹30 | −5% | ₹28.50 |
| Jam | ₹100 | −8% | ₹92.00 |
| Apples | ₹280 | −8% | ₹257.60 |
| Oil | ₹120 | +10% | ₹132.00 |
| Dal | ₹80 | +10% | ₹88.00 |
Part 7 — A Challenging Ratio-Division Problem on a Line Segment (Q14)
Question: Points P and Q lie on segment AB, on the same side of its midpoint. P divides AB in the ratio 2 : 3, and Q divides AB in the ratio 3 : 4. If PQ = 2, find the length of AB.
Both P and Q sit between A's midpoint and B, with P closer to A than Q — so PB is longer than QB, and PQ = PB − QB.
The trick is to express both PB and QB as a fraction of the whole length AB, then subtract.
Common Mistakes to Avoid
- Forgetting unit conversion before forming a ratio: As in Q1(ii), litres and millilitres (or any mismatched units) must be converted to the same unit first.
- Multiplying the wrong terms in a compound ratio: Always multiply antecedent × antecedent and consequent × consequent — never antecedent × consequent.
- Forgetting to invert a ratio when asked: In Q4, the "inverse ratio of 4 : 5" is 5 : 4, not 4 : 5 — missing this flip changes the entire answer.
- Mixing up "increased by" and the final new value: Q12 and Q13 ask for the change and the new total separately — always re-read which one the question wants.
- Assuming PQ = PB + QB instead of PB − QB: In problems like Q14, carefully figure out the actual order of the points on the line before deciding whether to add or subtract two segment lengths.
- Not double-checking with cross-multiplication: Whenever a ratio equation involves an unknown (like Q2, Q3), cross-multiplying is the safest way to isolate that unknown without sign or fraction errors.
Quick Reference — All 14 Answers at a Glance
| Q.No | Scenario | Key Result |
|---|---|---|
| 1(i) | Working hours, 6 hrs & 8 hrs | 3 : 4 |
| 1(ii) | Milk, 8 L & 750 mL | 32 : 3 |
| 1(iii) | Speeds, 15 km/h & 30 km/h | 1 : 2 |
| 2 | Compound ratio: 5:8 & 3:7 = 45:x | x = 168 |
| 3 | Compound ratio: 7:5 & 8:x = 84:60 | x = 8 |
| 4 | 3:4 compound with inverse of 4:5 | x = 48 |
| 5 | Teachers for 400 students (ratio 3:60) | 20 teachers |
| 6 | All 6 side ratios of an 8-6-10 triangle | 4:3, 3:4, 3:5, 5:3, 5:4, 4:5 |
| 7 | Below/above 75% marks (9 of 24) | 3 : 5 |
| 8 | Vowels : consonants in "MISSISSIPPI" | 4 : 7 |
| 9 | 25% profit share = ₹2080 | Total profit = ₹8320 |
| 10 | ΔABC vs ΔXYZ side ratios | All 1:2 — sides are in proportion |
| 11 | 5-item supermarket price table | ₹28.50, ₹92, ₹257.60, ₹132, ₹88 |
| 12 | Club enrolment, 4% decrease from 2075 | Decrease 83; new total 1992 |
| 13 | Cotton yield, 20% increase from 1720 | 2064 bags |
| 14 | Points P, Q dividing AB; PQ = 2 | AB = 70 units |
What This Exercise Prepares You For
Exercise 5.1 directly applies the formulas from the chapter introduction on ratio, proportion, compound ratio and percentage — if any step above felt unfamiliar, that's the right place to revise the underlying rule before continuing.
The percentage-change skills practised in Q11, Q12, and Q13 carry forward directly into the chapter's next exercises on profit, loss, discount, and simple interest, while the ratio-of-sides idea in Q6 and Q10 is a first taste of triangle similarity, a concept explored in much greater depth in the Triangles chapter in Class 9.