Exercise 5.2 — Discounts and GST

Discounts, profit and loss, Goods and Service Tax.

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Exercise 5.2 – Comparing Quantities Using Proportion (Profit, Loss, Discount & GST)

Exercise 5.2 of Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus) brings together everything you've learned about percentages and applies it to real-life money situations: profit and loss, discount, VAT, and GST (Goods and Services Tax). Every problem in this exercise is essentially the same percentage formula applied in a different shopping, business, or billing context.

Once you understand the core relationships between Cost Price (C.P.), Selling Price (S.P.), Marked Price (M.P.), and the percentage change, all 16 questions in this exercise become a matter of identifying which formula to use and substituting the correct values.

Key Formulas You Must Know

These four formula groups cover every single problem in Exercise 5.2. Keep this table handy while solving — almost every question is a direct application of one of these.

ConceptFormulaUsed In
DiscountDiscount = (Discount % ÷ 100) × Marked PriceQ5, Q13
Selling Price (with discount)S.P. = M.P. × (100 − discount %) ÷ 100Q5, Q13
ProfitProfit = S.P. − C.P. (when S.P. > C.P.)Q7, Q8, Q12
LossLoss = C.P. − S.P. (when C.P. > S.P.)Q8, Q11
Profit %Profit % = (Profit ÷ C.P.) × 100Q7, Q8, Q12
Loss %Loss % = (Loss ÷ C.P.) × 100Q8, Q11
S.P. from Profit %S.P. = C.P. × (100 + profit %) ÷ 100Q8, Q9, Q10
C.P. from S.P. and Profit %C.P. = S.P. × 100 ÷ (100 + profit %)Q9, Q10
Original Price from GST-included BillOriginal Price = Bill Amount × 100 ÷ (100 + GST %)Q14
GST AmountGST = (GST % ÷ 100) × Original PriceQ15
💡 The golden rule: Profit/loss percentages and discount percentages are always calculated on the Cost Price or Marked Price — never on the Selling Price, unless the question specifically says so. Mixing this up is the #1 mistake students make.
Question 1
Estimating Internet Users After a Percentage Increase
Percentage Increase

In 2012, there were 36.4 crore internet users worldwide. Over the next ten years, this number was estimated to increase by 125%. We need to find the estimated number of users in 2022.

A 125% increase means the new value is 225% of the original (100% original + 125% increase = 225%). So we multiply 36.4 crore by 225/100.

New users (2022) = 36.4 × (100 + 125) / 100
= 36.4 × 225 / 100
= 81.9 crore
∴ Estimated internet users in 2022 = 81.9 crore
New Value = Original Value × (100 + % increase) / 100
Question 2
House Rent Increasing by 5% Each Year (Compound Growth)
Repeated Percentage Increase

The monthly rent of a house is ₹2500, and it increases by 5% at the end of each year. We need the rent after 2 years. The key idea here is that the second year's increase is calculated on the already increased rent — this is the same logic as compound interest.

Step 1: Rent After 1 Year

Rent after 1 year = 2500 × (100 + 5) / 100 = 2500 × 105/100
= ₹2625

Step 2: Rent After 2 Years

Rent after 2 years = 2625 × (100 + 5) / 100 = 2625 × 105/100
= 11025/4
= ₹2756.25
💡 Why not just calculate 10% once? Because 5% + 5% ≠ 10% in successive increases. Each 5% is applied to a different (larger) base, so the total increase over 2 years is slightly more than 10% — exactly the same principle used for compound interest in later chapters.
Question 3
Share Price Changing Over Three Days (Increase Then Decrease)
Successive Percentage Change

A company's share price was ₹7.50 on Monday. It changed by different percentages on three consecutive days: +6% on Tuesday, −1.5% on Wednesday, and −2% on Thursday. Each day's change is applied to the previous day's closing price, not the original Monday price.

Tuesday (increase by 6%)

7.50 × (100 + 6)/100 = 7.50 × 105.../100
= ₹7.95

Wednesday (decrease by 1.5%)

7.95 × (100 − 1.5)/100 = 7.95 × 98.5/100
= ₹7.83075

Thursday (decrease by 2%)

7.83075 × (100 − 2)/100 = 7.83075 × 98/100
= ₹7.674135 ≈ ₹7.674
📐 Friday's opening price = Thursday's closing price = approximately ₹7.674. Always carry forward the previous day's result — never go back to the original ₹7.50 for the second or third calculation.
Question 4
Enlarging a Drawing Using a Xerox (Photocopy) Machine at 150%
Percentage of a Quantity

Reshma has a drawing measuring 2 cm by 4 cm and sets the photocopier to 150% to enlarge it. Setting a copier to 150% means every dimension of the original becomes 150% of its original value — this is a direct "percentage of a quantity" calculation applied to both the width and the length.

New width = 150% of 2 cm = (150/100) × 2 = 3 cm
New length = 150% of 4 cm = (150/100) × 4 = 6 cm
∴ New dimensions of the copy = 3 cm × 6 cm
💡 Notice the enlarged drawing keeps the same ratio as the original (2:4 = 1:2, and 3:6 = 1:2). Percentage enlargement always preserves the shape's proportions.
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Question 5
Finding the Selling Price After a Discount
Discount

A book's printed (marked) price is ₹150 and the shop offers a 15% discount. We need the actual amount the customer pays — this is a direct application of the selling price formula for discounts.

S.P. = Marked Price × (100 − discount %) / 100
S.P. = 150 × (100 − 15)/100 = 150 × 85/100
= 1275/10
∴ Amount to be paid = ₹127.50
Question 6
Finding the Discount Percentage from Marked Price and Selling Price
Discount Percentage

A gift item marked at ₹176 was sold for ₹165. This time we are given the actual discount in rupees implicitly (the difference between marked and selling price) and asked to express it as a percentage of the marked price.

Discount = Marked Price − Selling Price = 176 − 165 = ₹11
Discount % = (Discount / Marked Price) × 100 = (11/176) × 100
= 100/16
∴ Discount percent = 6.25%
Question 7
Profit Percentage When Some Stock Is Damaged
Profit & Loss with Wastage

A shopkeeper bought 200 bulbs at ₹10 each, but 5 bulbs got fused (became scrap and unsellable). The remaining 195 bulbs were sold at ₹12 each. The trick here is that the Cost Price is based on all 200 bulbs (the shopkeeper paid for all of them), but the Selling Price only comes from the 195 bulbs actually sold.

Total C.P. = 200 × ₹10 = ₹2000
Bulbs sold = 200 − 5 = 195
Total S.P. = 195 × ₹12 = ₹2340
Since S.P. > C.P., Gain = S.P. − C.P. = 2340 − 2000 = ₹340
Gain % = (340/2000) × 100
∴ Gain percent = 17%
💡 Common mistake: Students often divide the cost price by 195 instead of 200, forgetting that the damaged bulbs were still paid for. Always read carefully whether the "loss" items still count toward the cost.
Question 8
Completing a Profit & Loss Table — Five Different Cases
Profit, Loss, Profit %, Loss %

This question gives a table with five rows, each row missing different values (Selling Price, Profit, Loss, Profit %, or Loss %). Each row tests a different rearrangement of the same core profit/loss formulas. The "Expenses" column (repairs, transport, etc.) must always be added to the Cost Price before any calculation.

RowCost Price + ExpensesTotal C.P.S.P.Profit / LossProfit % / Loss %
1₹750 + ₹50₹800₹880Profit = ₹80Profit % = 10%
2₹4500 + ₹500₹5000₹4000Loss = ₹1000Loss % = 25%
3₹46,000 + ₹4000₹50,000₹60,000Profit = ₹10,000Profit % = 20%
4₹300 + ₹50₹350₹392Profit = ₹42Profit % = 12% (given)
5₹330 + ₹20₹350₹315Loss = ₹35Loss % = 10% (given)

Row 1: Finding S.P. and Profit % (C.P. and Profit Given)

Total C.P. = 750 + 50 = ₹800; Profit = ₹80
S.P. = C.P. + Profit = 800 + 80 = ₹880
Profit % = (80/800) × 100
= 10%

Row 2: Finding S.P. and Loss % (C.P. and Loss Given)

Total C.P. = 4500 + 500 = ₹5000; Loss = ₹1000
S.P. = C.P. − Loss = 5000 − 1000 = ₹4000
Loss % = (1000/4000) × 100
= 25%

Row 3: Finding Profit and Profit % (C.P. and S.P. Given)

Total C.P. = 46000 + 4000 = ₹50,000; S.P. = ₹60,000
Since S.P. > C.P., Profit = S.P. − C.P. = 60000 − 50000 = ₹10,000
Profit % = (10000/50000) × 100
= 20%

Row 4: Finding S.P. and Profit (C.P. and Profit % Given)

Total C.P. = 300 + 50 = ₹350; Profit % = 12%
S.P. = C.P. × (100 + 12)/100 = 350 × 112/100 = 3920/10
= ₹392
Profit = S.P. − C.P. = 392 − 350
= ₹42

Row 5: Finding S.P. and Loss (C.P. and Loss % Given)

Total C.P. = 330 + 20 = ₹350; Loss % = 10%
S.P. = C.P. × (100 − 10)/100 = 350 × 90/100
= ₹315
Loss = C.P. − S.P. = 350 − 315
= ₹35
Question 9
Finding a New Selling Price for a Different Profit Percentage
C.P. from S.P. and Profit %

A table was sold for ₹2142 at a gain of 5%. We're asked at what price it should be sold to gain 10% instead. This requires a two-step approach: first work backward from the given S.P. and profit % to find the C.P., then use the C.P. to find the new S.P. for the desired profit %.

Step 1: Find the Cost Price

C.P. = S.P. × 100 / (100 + profit %) = 2142 × 100/105
= ₹2040

Step 2: Find New S.P. for 10% Gain

New S.P. = C.P. × (100 + 10)/100 = 2040 × 110/100
= 204 × 11
∴ New S.P. = ₹2244
Question 10
A Chain of Buying and Selling (Two Transactions)
Chain Profit & Loss

Gopi sold a watch to Ibrahim at a 12% gain. Ibrahim then sold it to John at a 5% loss. John paid ₹1330. We need to find how much Gopi sold it for. The key insight is that Ibrahim's selling price to John equals John's cost price, and working backward gives us Ibrahim's cost price — which is also Gopi's selling price.

Gopi --(12% gain)--> Ibrahim --(5% loss)--> John pays ₹1330

Step: Find Ibrahim's Cost Price (= Gopi's Selling Price)

S.P. for Ibrahim (= C.P. for John) = ₹1330, Loss % = 5%
C.P. for Ibrahim = S.P. × 100/(100 − loss %) = 1330 × 100/95
= ₹1400
📐 ∴ Gopi sold the watch to Ibrahim for ₹1400. Notice we never needed to use the 12% figure at all — it was extra information not required for this particular question. Always check which numbers are actually needed before calculating.
Question 11
Calculating Loss and Loss Percentage on a House Sale
Loss & Loss Percent

Madhu and Kavitha bought a house for ₹3,20,000 and had to sell it for ₹2,80,000 due to financial difficulties. We need both the actual loss amount and the loss percentage.

Loss = C.P. − S.P. = 320000 − 280000
(a) Loss incurred = ₹40,000
Loss % = (40000/320000) × 100
(b) Loss percentage = 12.5%
Question 12
Profit Percentage Including Repair Expenses
Profit % with Additional Expenses

A showroom owner bought a second-hand car for ₹1,50,000 and spent ₹20,000 on repairs and painting before selling it for ₹2,00,000. As with Question 7, the repair cost must be added to the cost price before finding profit or loss.

Total C.P. = 150000 + 20000 = ₹1,70,000
S.P. = ₹2,00,000; since S.P. > C.P., it's a profit
Profit = S.P. − C.P. = 200000 − 170000 = ₹30,000
Profit % = (30000/170000) × 100 = 300/17
∴ Profit percentage = 17 (11/17)%
Question 13
Calculating a Final Bill After VAT Plus a Discount
Discount on a VAT-Inclusive Bill

Lalitha's hotel bill was ₹1450, already including 5% VAT. The hotel owner then gave her an 8% discount on the total bill amount. We don't need to remove the VAT first — the discount is applied directly to the final billed amount of ₹1450.

Amount to pay = Bill × (100 − discount %)/100 = 1450 × (100 − 8)/100
= 1450 × 92/100
= 29 × 46
∴ Amount to be paid = ₹1334
💡 The VAT was already part of the ₹1450 bill, so the 8% discount is simply applied on top of that figure — there's no need to separate VAT and base price for this question.
Question 14
Finding the Original Price When GST Is Already Included
Reverse GST Calculation

When a bill shows the final amount with GST already added, you must work backward to find the original (pre-tax) price. The formula divides by (100 + GST%) instead of multiplying — because the bill amount represents 100% + GST% of the original price.

Original Price = Bill Amount × 100 / (100 + GST %)
ItemGST %Bill Amount (₹)Original Price (₹)
(i) Diamond3%10,30010,000
(ii) Pressure Cooker12%3,3603,000
(iii) Face Powder28%256200

(i) Diamond — 3% GST, Bill ₹10,300

Original Price = 10300 × 100/(100 + 3) = 10300 × 100/103
= ₹10,000

(ii) Pressure Cooker — 12% GST, Bill ₹3,360

Original Price = 3360 × 100/(100 + 12) = 3360 × 100/112
= ₹3,000

(iii) Face Powder — 28% GST, Bill ₹256

Original Price = 256 × 100/(100 + 28) = 256 × 100/128
= ₹200
Question 15
Calculating GST Amount and Final Purchase Price (Forward GST)
Forward GST Calculation

Unlike Question 14, this is a forward GST problem. A cellphone company fixes the price at ₹4500, and a dealer pays 12% GST additionally on top of this. We need both the GST amount and the total purchase price the dealer pays.

GST amount = 12% of 4500 = (12/100) × 4500
= 12 × 45
GST paid by dealer = ₹540
Purchase price = Fixed Price + GST = 4500 + 540
∴ Purchase price of cellphone = ₹5040
📐 Q14 vs Q15 — don't confuse these two GST types: In Q14, GST was already inside the bill, so we divided by (100 + GST%). In Q15, GST is added separately, so we calculate it as a percentage of the price and add it on. Reading the question carefully tells you which type applies.
Question 16
Finding the Smallest Price for Which Sales Tax Gives a Whole Rupee Amount
Algebraic Application — HOTS

This is a Higher Order Thinking Skills (HOTS) problem. A Super Bazaar prices items in rupees and paise, and after adding 4% sales tax, the final amount must come out to exactly 'n' rupees (a whole number) with no rounding. We need the smallest such 'n'.

Let the original price be ₹x. Adding 4% tax gives the final amount n:

n = x + 4% of x = x × (100 + 4)/100 = x × 104/100 = 26x/25
Rearranging: x = 25n/26
For x to be a terminating, exact value (in rupees and paise), n must be a factor of 26
Factors of 26: 1, 2, 13, 26
The smallest factor that gives a valid, sensible price for x is n = 13
∴ Smallest value of n = 13
💡 This problem tests algebraic reasoning combined with percentages — a preview of how percentage relationships will be expressed using variables in Class 9 and Class 10 algebra chapters.

Common Mistakes to Avoid in Exercise 5.2

  • Calculating percentage on the wrong base: Profit %, Loss %, and Discount % are always calculated on the Cost Price or Marked Price, never on the Selling Price (unless explicitly stated otherwise).
  • Forgetting additional expenses: Repairs, transport, or other costs (as in Q7, Q8 Row 1-2, and Q12) must be added to the Cost Price before any profit/loss calculation.
  • Confusing GST-included vs GST-additional problems: If the bill already includes GST (Q14), divide by (100 + GST%). If GST is charged on top of a fixed price (Q15), multiply by GST% and add it separately.
  • Using the original value for successive percentage changes: In problems like Q2 and Q3, each new percentage change applies to the most recent value, not the original starting value.
  • Ignoring shape/scenario-specific properties: In chain transactions (Q10), carefully track who is the buyer and who is the seller at each stage — the same number can be both an S.P. and a C.P. depending on perspective.
📐 Board exam tip: In CBSE, Telangana, and Andhra Pradesh exams, marks are awarded for showing the correct formula and substitution step — even if there's a small arithmetic slip at the end. Always write the formula first, then substitute values clearly.

What Exercise 5.2 Prepares You For

The percentage-based reasoning in this exercise — increase, decrease, reverse calculation, and successive changes — forms the foundation for earlier topics in Comparing Quantities Using Proportion as well as more advanced applications later. The "successive percentage change" idea from Questions 2 and 3 directly leads into compound interest calculations, while the algebraic approach in Question 16 is a stepping stone toward forming and solving linear equations.

Strong command over profit, loss, discount, and GST is also extremely useful for Class 9 algebraic expressions, where similar real-world relationships are expressed and manipulated using variables instead of fixed numbers.

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