Exercise 6.3 — Division Method

Finding square root by division method, square roots of decimal numbers.

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Exercise 6.3 – Square Root by Long Division Method

Exercise 6.3 of Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus) introduces the long division method for finding square roots — a powerful technique that works for any number, including large numbers and decimals, where prime factorisation becomes slow or impossible. This exercise has 8 questions covering four types of problems: finding square roots of integers, finding square roots of decimals, adjusting a number by subtraction or addition to make it a perfect square, and estimating square roots to the nearest whole number.

Unlike the prime factorisation method from Exercise 6.2, the long division method works even when a number has large or awkward prime factors. It is a key technique tested in board exams across Telangana, Andhra Pradesh, and CBSE Class 8.

How the Long Division Method Works — Step-by-Step

The long division method for square roots is built on a simple idea: group the digits in pairs starting from the decimal point (or from the right for whole numbers), then find how many times a carefully chosen divisor fits into each successive group. Here is the complete procedure:

1
Group the digits in pairs from right to left. For example, 1089 becomes 10 | 89 and 2304 becomes 23 | 04. If there is an odd digit at the left, it forms a group of one. For decimals, pair from the decimal point outward in both directions.
2
Find the largest integer whose square ≤ the first group. This is your first quotient digit. Write it above and its square below the first group. Subtract to get the first remainder.
3
Bring down the next pair alongside the remainder to form the new dividend.
4
Double the current quotient to get the trial divisor. Write it to the left with a blank digit at the end (e.g., if quotient so far is 3, write "6_").
5
Find the largest digit d such that (trial divisor with d appended) × d ≤ new dividend. This digit d becomes the next quotient digit. Subtract and bring down the next pair.
6
Repeat until the remainder is 0 (perfect square) or you have enough decimal places. The quotient built up step by step is the square root.
💡 Key rule for decimals: Place the decimal point in the quotient exactly when you cross the decimal point in the number. Pair the decimal digits going right from the decimal point. This is why √2.56 = 1.6 and not 16 or 0.16.

Question 1 — Find Square Roots by Long Division Method

Question 1 (i)
Find √1089
Long Division — Integer

Group the digits: 10 | 89

Long Division — √1089
Quotient digit 13 (since 3² = 9 ≤ 10)
Subtract 9 from 10Remainder = 1
Bring down 89New dividend = 189
Trial divisor2 × 3 = 6 → try 6_
Find d63 × 3 = 189 ≤ 189 → d = 3
Subtract 189Remainder = 0
√1089= 33
√1089 = 33  Verify: 33 × 33 = 1089 ✓
Question 1 (ii)
Find √2304
Long Division — Integer

Group the digits: 23 | 04

Long Division — √2304
Quotient digit 14 (since 4² = 16 ≤ 23)
Subtract 16 from 23Remainder = 7
Bring down 04New dividend = 704
Trial divisor2 × 4 = 8 → try 8_
Find d88 × 8 = 704 ≤ 704 → d = 8
Subtract 704Remainder = 0
√2304= 48
√2304 = 48  Verify: 48 × 48 = 2304 ✓
Question 1 (iii)
Find √7744
Long Division — Integer

Group the digits: 77 | 44

Long Division — √7744
Quotient digit 18 (since 8² = 64 ≤ 77)
Subtract 64 from 77Remainder = 13
Bring down 44New dividend = 1344
Trial divisor2 × 8 = 16 → try 16_
Find d168 × 8 = 1344 ≤ 1344 → d = 8
Subtract 1344Remainder = 0
√7744= 88
√7744 = 88  Verify: 88 × 88 = 7744 ✓
Question 1 (iv)
Find √6084
Long Division — Integer

Group the digits: 60 | 84

Long Division — √6084
Quotient digit 17 (since 7² = 49 ≤ 60)
Subtract 49 from 60Remainder = 11
Bring down 84New dividend = 1184
Trial divisor2 × 7 = 14 → try 14_
Find d148 × 8 = 1184 ≤ 1184 → d = 8
Subtract 1184Remainder = 0
√6084= 78
√6084 = 78  Verify: 78 × 78 = 6084 ✓
Question 1 (v)
Find √9025
Long Division — Integer

Group the digits: 90 | 25

Long Division — √9025
Quotient digit 19 (since 9² = 81 ≤ 90)
Subtract 81 from 90Remainder = 9
Bring down 25New dividend = 925
Trial divisor2 × 9 = 18 → try 18_
Find d185 × 5 = 925 ≤ 925 → d = 5
Subtract 925Remainder = 0
√9025= 95
√9025 = 95  Verify: 95 × 95 = 9025 ✓
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Question 2 — Square Roots of Decimal Numbers

For decimal numbers, pair the digits on each side of the decimal point separately — going left for the integer part and going right for the decimal part. Place the decimal point in the square root exactly when you bring down the first decimal pair. The method is otherwise identical to the integer case.

Question 2 (i)
Find √2.56
Long Division — Decimal

Group as: 2 . 56 → integer part: "2" (one group), decimal part: "56" (one pair)

Long Division — √2.56
Quotient digit 11 (since 1² = 1 ≤ 2)
Subtract 1 from 2Remainder = 1
Bring down .56New dividend = 156 (place decimal point in quotient)
Trial divisor2 × 1 = 2 → try 2_
Find d26 × 6 = 156 ≤ 156 → d = 6
Subtract 156Remainder = 0
√2.56= 1.6
√2.56 = 1.6  Verify: 1.6 × 1.6 = 2.56 ✓
Question 2 (ii)
Find √18.49
Long Division — Decimal

Group as: 18 . 49 → integer part: "18", decimal part: "49"

Long Division — √18.49
Quotient digit 14 (since 4² = 16 ≤ 18)
Subtract 16 from 18Remainder = 2
Bring down .49New dividend = 249
Trial divisor2 × 4 = 8 → try 8_
Find d83 × 3 = 249 ≤ 249 → d = 3
Subtract 249Remainder = 0
√18.49= 4.3
√18.49 = 4.3  Verify: 4.3 × 4.3 = 18.49 ✓
Question 2 (iii)
Find √68.89
Long Division — Decimal

Group as: 68 . 89

Long Division — √68.89
Quotient digit 18 (since 8² = 64 ≤ 68)
Subtract 64 from 68Remainder = 4
Bring down .89New dividend = 489
Trial divisor2 × 8 = 16 → try 16_
Find d163 × 3 = 489 ≤ 489 → d = 3
Subtract 489Remainder = 0
√68.89= 8.3
√68.89 = 8.3  Verify: 8.3 × 8.3 = 68.89 ✓
Question 2 (iv)
Find √84.64
Long Division — Decimal

Group as: 84 . 64

Long Division — √84.64
Quotient digit 19 (since 9² = 81 ≤ 84)
Subtract 81 from 84Remainder = 3
Bring down .64New dividend = 364
Trial divisor2 × 9 = 18 → try 18_
Find d182 × 2 = 364 ≤ 364 → d = 2
Subtract 364Remainder = 0
√84.64= 9.2
√84.64 = 9.2  Verify: 9.2 × 9.2 = 84.64 ✓

Questions 3 to 7 — Applying the Division Method

Question 3
Find the least number to be subtracted from 4000 to make it a perfect square
Subtraction to get perfect square

The strategy: find √4000 by long division and note the remainder at the end. That remainder is the number which, when subtracted, leaves the largest perfect square ≤ 4000.

Group 4000 as: 40 | 00

Long Division — √4000
Quotient digit 16 (since 6² = 36 ≤ 40)
Subtract 36 from 40Remainder = 4
Bring down 00New dividend = 400
Trial divisor2 × 6 = 12 → try 12_
Find d123 × 3 = 369 ≤ 400; 124 × 4 = 496 > 400 → d = 3
Subtract 369Remainder = 31
Quotient = 63Remainder = 31
4000 − 31 = 3969 = 63²

The remainder 31 is the excess. Subtracting it gives 3969, which is a perfect square.

✅ The least number to be subtracted from 4000 to make it a perfect square is 31. The resulting perfect square is 3969 = 63².
Question 4
Find the side of a square whose area is 4489 sq. cm
Word Problem — Geometry

If the side of the square is x cm, then area = x² = 4489. So x = √4489. Group as: 44 | 89

Long Division — √4489
Quotient digit 16 (since 6² = 36 ≤ 44)
Subtract 36 from 44Remainder = 8
Bring down 89New dividend = 889
Trial divisor2 × 6 = 12 → try 12_
Find d127 × 7 = 889 ≤ 889 → d = 7
Subtract 889Remainder = 0
√4489= 67
Side = √4489 = 67 cm
✅ The side of the square = 67 cm.
Question 5
8289 plants in a square arrangement — 8 plants left over. Find plants per row.
Word Problem — Square root application

Since 8 plants could not be arranged in the square, the plants actually arranged form a perfect square: 8289 − 8 = 8281. If each row has x plants and there are x rows, then x² = 8281.

Group 8281 as: 82 | 81

Long Division — √8281
Quotient digit 19 (since 9² = 81 ≤ 82)
Subtract 81 from 82Remainder = 1
Bring down 81New dividend = 181
Trial divisor2 × 9 = 18 → try 18_
Find d181 × 1 = 181 ≤ 181 → d = 1
Subtract 181Remainder = 0
√8281= 91
✅ The number of plants in each row = 91.
Question 6
Find the least perfect square with four digits
Conceptual — Perfect squares

The smallest four-digit number is 1000. Find √1000 by long division and check what the next quotient would be — squaring it gives the least four-digit perfect square.

Group 1000 as: 10 | 00

Long Division — √1000
Quotient digit 13 (since 3² = 9 ≤ 10)
Subtract 9 from 10Remainder = 1
Bring down 00New dividend = 100
Trial divisor2 × 3 = 6 → try 6_
Find d61 × 1 = 61 ≤ 100; 62 × 2 = 124 > 100 → d = 1
Subtract 61Remainder = 39 (not zero — 1000 is NOT a perfect square)
Floor quotient= 31

Since √1000 lies between 31 and 32, the largest three-digit perfect square is 31² = 961 and the least four-digit perfect square is the next one: 32² = 1024.

32² = 32 × 32 = 1024
✅ The least perfect square with four digits = 1024.
Question 7
Find the least number to add to 6412 to make it a perfect square
Addition to get perfect square

The strategy: find √6412 by long division. The quotient gives the floor square root (call it n). The next perfect square above 6412 is (n+1)². The number to add is (n+1)² − 6412.

Group 6412 as: 64 | 12

Long Division — √6412
Quotient digit 18 (since 8² = 64 ≤ 64)
Subtract 64 from 64Remainder = 0
Bring down 12New dividend = 12
Trial divisor2 × 8 = 16 → try 16_
Find d160 × 0 = 0 ≤ 12; 161 × 1 = 161 > 12 → d = 0
Subtract 0Remainder = 12 (6412 is NOT a perfect square)
Floor quotient= 80

√6412 lies between 80 and 81. The next perfect square above 6412 is 81² = 6561.

6561 − 6412 = 149
✅ The least number to add to 6412 = 149. The resulting perfect square is 6561 = 81².

Question 8 — Estimate Square Roots to the Nearest Whole Number

When a number is not a perfect square, you can estimate its square root by identifying which two consecutive perfect squares it falls between, then choosing the nearer one. This is a quick mental technique useful in CBSE and state board MCQs and estimation questions.

Method: Find n such that n² ≤ given number < (n+1)². If the number is closer to n², √ ≈ n; if closer to (n+1)², √ ≈ n+1.

Question 8 (i)
Estimate √97 to the nearest whole number
9² = 81 < 97 < 100 = 10²
97 − 81 = 16    |    100 − 97 = 3
97 is closer to 100 → √97 ≈ 10
Question 8 (ii)
Estimate √250 to the nearest whole number
15² = 225 < 250 < 256 = 16²
250 − 225 = 25    |    256 − 250 = 6
250 is closer to 256 → √250 ≈ 16
Question 8 (iii)
Estimate √780 to the nearest whole number
27² = 729 < 780 < 784 = 28²
780 − 729 = 51    |    784 − 780 = 4
780 is closer to 784 → √780 ≈ 28

Exercise 6.3 — Quick Answer Summary

QuestionTypeAnswer
1(i) √1089Long division — integer33
1(ii) √2304Long division — integer48
1(iii) √7744Long division — integer88
1(iv) √6084Long division — integer78
1(v) √9025Long division — integer95
2(i) √2.56Long division — decimal1.6
2(ii) √18.49Long division — decimal4.3
2(iii) √68.89Long division — decimal8.3
2(iv) √84.64Long division — decimal9.2
3. Subtract from 4000Make perfect square31 (→ 3969 = 63²)
4. Side of square (area 4489)Word problem67 cm
5. Plants per row (8281 planted)Word problem91
6. Least 4-digit perfect squareConceptual1024 = 32²
7. Add to 6412Make perfect square149 (→ 6561 = 81²)
8(i) √97 ≈Estimation10
8(ii) √250 ≈Estimation16
8(iii) √780 ≈Estimation28

Common Mistakes to Avoid in Exercise 6.3

  • Wrong digit grouping: Always pair digits from the decimal point outward. "1089" groups as "10|89", not "1|08|9". One wrong group ruins the entire calculation.
  • Forgetting to double the quotient for the trial divisor: The trial divisor is always 2 × (current quotient), not the quotient itself. Missing this step is the most common error in board exams.
  • Decimal square roots — wrong placement of decimal point: The decimal point goes in the answer exactly when you cross the decimal point in the number. Practice this with 2(i)–(iv) until it is automatic.
  • Subtract vs Add questions — confusing the two: For Q3 (subtract), the answer is the remainder in the division. For Q7 (add), the answer is next perfect square minus the given number. These are opposite operations.
  • Estimation — choosing the wrong square: Always compute both differences (number − lower square) and (upper square − number) and pick the smaller one. Do not guess by eye.
📝 Board exam tip (Telangana & AP): In the long division method, marks are awarded for each step — the grouping, the trial divisor, the subtraction, and the final answer. Even if your final answer is correct, missing intermediate steps can cost marks. Write every step clearly.

What Exercise 6.3 Prepares You For

The long division method is the last major technique in Chapter 6. Together with the prime factorisation method from Exercise 6.2, it gives you a complete toolkit for handling square roots at Class 8 level.

The estimation skill from Question 8 directly connects to irrational numbers in Class 9, where you locate surds like √2 and √3 on the number line by identifying which consecutive integers they fall between — the exact same reasoning used here. The subtraction and addition technique (Questions 3 and 7) also reappears in completing the square for quadratic equations in Class 9 and 10.

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