Exercise 6.4 — Cubes and Cube Roots
Cubes and cube roots with interesting patterns.
Exercise 6.4 – Cubes, Perfect Cubes & the Prime Factorisation Method
Exercise 6.4 from Chapter 6, "Square Roots and Cube Roots," of Class 8 Mathematics (CBSE, Telangana & Andhra Pradesh syllabus) introduces the idea of a cube of a number and teaches students how to use prime factorisation to test whether a number is a perfect cube. The exercise also covers practical applications — finding the smallest number to multiply or divide by to make a number a perfect cube, and counting unit cubes that fit inside a cuboid.
This exercise builds directly on the idea of square numbers covered in earlier exercises of this chapter, and the same prime factorisation skills will be reused throughout Class 8, 9, and 10 whenever you need to simplify roots or check divisibility.
What Is a Cube Number?
When a number is multiplied by itself three times, the result is called the cube of that number. If a number can be written as a product of three equal factors, it is called a perfect cube or cubic number.
Cube of n = n × n × n = n³
This idea connects to a visual model using unit cubes. A cube made of side-length 1 unit uses 1×1×1 = 1 unit cube. A cube of side-length 2 units is built from 2×2×2 = 8 unit cubes, and a cube of side-length 3 units needs 3×3×3 = 27 unit cubes. This pattern — side length cubed equals the total number of unit cubes — is exactly what the formula n³ represents.
Cubes of Numbers from 1 to 20
Memorising this table makes recognising perfect cubes much faster during exams:
| Number | Cube | Number | Cube |
|---|---|---|---|
| 1³ | 1 | 11³ | 1331 |
| 2³ | 8 | 12³ | 1728 |
| 3³ | 27 | 13³ | 2197 |
| 4³ | 64 | 14³ | 2744 |
| 5³ | 125 | 15³ | 3375 |
| 6³ | 216 | 16³ | 4096 |
| 7³ | 343 | 17³ | 4913 |
| 8³ | 512 | 18³ | 5832 |
| 9³ | 729 | 19³ | 6859 |
| 10³ | 1000 | 20³ | 8000 |
Units Digit Pattern of Cubes
Another useful rule is that the cube of an even number is always even, and the cube of an odd number is always odd. The units digit of a number's cube follows a predictable pattern, which is especially helpful for quickly estimating cube roots:
| Units Digit of the Number | Units Digit of the Cube |
|---|---|
| 0 | 0 |
| 1 | 1 |
| 2 | 8 |
| 3 | 7 |
| 4 | 4 |
| 5 | 5 |
| 6 | 6 |
| 7 | 3 |
| 8 | 2 |
| 9 | 9 |
Exercise 6.4 – Solved Questions, Step by Step
This question simply asks for the cube of four given numbers — a good way to practise multiplying a number by itself three times.
| Number | Calculation | Cube |
|---|---|---|
| (i) 8 | 8 × 8 × 8 | 512 |
| (ii) 16 | 16 × 16 × 16 | 4096 |
| (iii) 21 | 21 × 21 × 21 | 9261 |
| (iv) 30 | 30 × 30 × 30 | 27000 |
The standard method to check if a number is a perfect cube is to write its prime factorisation and see whether every prime factor appears in groups of exactly three. If all prime factors group perfectly in threes, the number is a perfect cube.
(i) Is 243 a Perfect Cube?
| 3 | 243 |
| 3 | 81 |
| 3 | 27 |
| 3 | 9 |
| 3 |
243 = 3 × 3 × 3 × 3 × 3 (five 3s in total). Since five cannot be split into a complete group of three with nothing left over, the prime factor 3 does not appear in a group of three. Therefore, 243 is not a perfect cube.
(ii) Is 516 a Perfect Cube?
| 2 | 516 |
| 2 | 258 |
| 3 | 129 |
| 43 |
516 = 2 × 2 × 3 × 43. None of the prime factors (2, 3, or 43) appear in groups of three. Therefore, 516 is not a perfect cube.
(iii) Is 729 a Perfect Cube?
| 3 | 729 |
| 3 | 243 |
| 3 | 81 |
| 3 | 27 |
| 3 | 9 |
| 3 |
729 = 3 × 3 × 3 × 3 × 3 × 3 (six 3s, which split perfectly into two groups of three). Since the prime factor 3 appears in complete groups of three, 729 is a perfect cube (in fact, 729 = 9³).
(iv) Is 8000 a Perfect Cube?
| 2 | 8000 |
| 2 | 4000 |
| 2 | 2000 |
| 2 | 1000 |
| 2 | 500 |
| 2 | 250 |
| 5 | 125 |
| 5 | 25 |
| 5 |
8000 = 2 × 2 × 2 × 2 × 2 × 2 × 5 × 5 × 5 (six 2s and three 5s — both group perfectly into threes). Therefore, 8000 is a perfect cube (8000 = 20³).
(v) Is 2700 a Perfect Cube?
| 2 | 2700 |
| 2 | 1350 |
| 3 | 675 |
| 3 | 225 |
| 3 | 75 |
| 5 | 25 |
| 5 |
2700 = 2 × 2 × 3 × 3 × 3 × 5 × 5. The factor 3 forms a complete group of three, but 2 (only two of them) and 5 (only two of them) do not. Therefore, 2700 is not a perfect cube.
| 2 | 8788 |
| 2 | 4394 |
| 13 | 2197 |
| 13 | 169 |
| 13 |
8788 = 2 × 2 × 13 × 13 × 13. The factor 13 already forms a perfect group of three, but the factor 2 appears only twice — one 2 short of a complete group of three. To fix this, multiply by one more 2.
Smallest number to multiply 8788 by, to get a perfect cube = 2
| 3 | 7803 |
| 3 | 2601 |
| 3 | 867 |
| 17 | 289 |
| 17 |
7803 = 3 × 3 × 3 × 17 × 17. The factor 3 forms a complete group of three, but 17 appears only twice — one 17 short of a complete group of three. To fix this, multiply by one more 17.
Smallest number to multiply 7803 by, to get a perfect cube = 17
| 2 | 8640 |
| 2 | 4320 |
| 2 | 2160 |
| 2 | 1080 |
| 2 | 540 |
| 2 | 270 |
| 3 | 135 |
| 3 | 45 |
| 3 | 15 |
| 5 |
8640 = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3 × 3 × 5 (six 2s and three 3s group perfectly, but 5 appears only once — leftover with no group). To fix this, divide by 5 so the leftover factor is removed and what remains becomes a perfect cube.
Smallest number to divide 8640 by, to get a perfect cube = 5
Ravi made a cuboid of plasticine with dimensions 12 cm × 8 cm × 3 cm using 1 cm unit cubes. To find the minimum number of unit cubes needed, multiply the three dimensions together — this is simply the volume of the cuboid.
Number of unit cubes = length × breadth × height = 12 × 8 × 3 = 288
So, Ravi needs a minimum of 288 unit cubes to build the cuboid. This question links the algebraic idea of "cube" to the geometric idea of volume — every unit cube occupies exactly 1 cm³, so counting unit cubes is the same as calculating the cuboid's volume in cubic centimetres.
This question uses logical reasoning about odd and even numbers rather than direct calculation — a useful shortcut for large powers that would be impractical to compute fully.
- Step 1: The product of two odd numbers is always odd. Since 3 is odd, 3¹¹ (3 multiplied by itself 11 times) is also odd.
- Step 2: Similarly, since 5 is odd, 5¹³ is also odd.
- Step 3: The sum of two odd numbers is always even. So 3¹¹ + 5¹³ is an even number.
- Step 4: The smallest prime number that divides any even number is always 2.
Smallest prime number dividing (3¹¹ + 5¹³) = 2
Common Mistakes to Avoid in Exercise 6.4
- Confusing squares with cubes: Squaring a number multiplies it by itself twice (n × n), while cubing multiplies it three times (n × n × n). Always re-check which operation the question asks for.
- Stopping prime factorisation too early: Always continue dividing until the quotient becomes 1. An incomplete factor tree can make a perfect cube look like it isn't one.
- Mixing up "multiply" and "divide" cases: If every prime factor except one is already in a group of three and that one factor needs just one more to complete its group, multiply. If a factor stands completely alone with no way to complete a group of three sensibly, divide it out.
- Forgetting to group factors correctly: When writing the prime factorisation, group identical factors together (e.g., write 2×2×2×2×2×2 as two groups of three 2s) to clearly see whether each prime appears in multiples of three.
- Arithmetic slips in large cubes: For numbers like 21³ or 30³, calculate step by step (first n×n, then multiply the result by n again) instead of trying to do it all in one go.
What Exercise 6.4 Prepares You For
The prime factorisation skills practised here are essential for the next step in this chapter — finding cube roots of perfect cubes using the prime factorisation method, where each group of three identical prime factors contributes one factor to the cube root. This naturally follows the techniques used for finding square roots earlier in this chapter, since both methods rely on grouping prime factors.
These ideas also reappear in Class 9 and Class 10 when simplifying expressions involving exponents and real numbers, and when working with algebraic identities involving cubes such as (a + b)³ and (a − b)³. Students preparing for CBSE, Telangana, or Andhra Pradesh board exams should be comfortable both calculating cubes directly and using prime factorisation to test for perfect cubes, as both types of questions appear regularly in exams.