Introduction to Trigonometry

Trigonometry and ratios in a right angle triangle.

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📐 Class 10 · Chapter 11 · Mathematics

Introduction to Trigonometry

Understand the six trigonometric ratios, how they are defined from a right-angled triangle, and how to apply them — step by step, with worked examples.

🌐 What is Trigonometry?

The word Trigonometry comes from three ancient Greek words — and understanding that etymology immediately tells you what the subject is about:

"TRI" Three
"GON" Sides
"METRON" Measure
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Definition Trigonometry is a branch of mathematics that studies the relationship between the side lengths and angles of a triangle — especially a right-angled triangle.

This chapter is part of the Class 10 Mathematics syllabus for CBSE, Telangana, and Andhra Pradesh boards. Mastering these ratios forms the foundation for topics like heights and distances, and advanced calculus later on.


📐 Parts of a Right-Angled Triangle

Before defining any ratio, you need to clearly identify the three sides of a right-angled triangle relative to a chosen angle. Consider △ABC with the right angle at B:

C B A Hypotenuse (AC) Opp side (BC) Adj side (AB) ∠A

With respect to ∠A:

  • Hypotenuse (AC) — the side opposite the right angle; always the longest side.
  • Opposite side (BC) — the side directly across from ∠A.
  • Adjacent side (AB) — the side next to ∠A (not the hypotenuse).
⚠️
Important! The "opposite" and "adjacent" sides change depending on which angle you are working with. The hypotenuse is always fixed.

🔬 Activity: Why Ratios Stay Constant in Similar Triangles

This is the key insight that gives birth to trigonometric ratios. Take four right-angled triangles that all share angle A but have different sizes. Measure the sides and compute the ratios:

Triangle Hypotenuse Opposite (to ∠A) Adjacent (to ∠A) Opp ÷ Hyp Adj ÷ Hyp
△ABP 543 4/5 3/5
△ACQ 1086 8/10 = 4/5 6/10 = 3/5
△ADR 15129 12/15 = 4/5 9/15 = 3/5
△AES 201612 16/20 = 4/5 12/20 = 3/5
Conclusion Even though the triangles are different sizes, the ratio Opposite ÷ Hypotenuse is always 4/5, and Adjacent ÷ Hypotenuse is always 3/5. This constant ratio depends only on the angle, not the size of the triangle. That is why we name these ratios sine and cosine!
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📊 The Six Trigonometric Ratios

For a right-angled triangle ABC (right angle at B), the six trigonometric ratios for angle A are defined as follows:

Ratio Symbol Definition In △ABC
Sine sin A Opposite ÷ Hypotenuse BC / AC
Cosine cos A Adjacent ÷ Hypotenuse AB / AC
Tangent tan A Opposite ÷ Adjacent BC / AB
Cosecant cosec A Hypotenuse ÷ Opposite AC / BC
Secant sec A Hypotenuse ÷ Adjacent AC / AB
Cotangent cot A Adjacent ÷ Opposite AB / BC

Quick Memory Reference:

sin A
Opp / Hyp
cos A
Adj / Hyp
tan A
Opp / Adj
cosec A
Hyp / Opp
sec A
Hyp / Adj
cot A
Adj / Opp
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Reciprocal Relationships cosec A = 1/sin A  |  sec A = 1/cos A  |  cot A = 1/tan A
Also: sin A / cos A = tan A  and  cos A / sin A = cot A

✏️ Worked Examples – Step by Step

Example 1 — Find sin C, cos C and tan C (Hyp = 13 cm, BC = 5 cm)
1
First find the missing side AB using Pythagoras: AC² = AB² + BC²  →  13² = AB² + 5²
2
169 = AB² + 25  →  AB² = 144  →  AB = 12 cm
3
Now apply the definitions with respect to ∠C. The opposite side to ∠C is AB, and the adjacent side is BC.
sin C = AB/AC = 12/13  |  cos C = BC/AC = 5/13  |  tan C = AB/BC = 12/5
Example 2 — △XYZ with ∠Y = 90°, XZ = 17 m, YZ = 15 m. Find sin X, cos Z, tan X.
1
Find XY: XZ² = XY² + YZ²  →  289 = XY² + 225  →  XY² = 64  →  XY = 8 m
2
sin X = opposite to ∠X ÷ hypotenuse = YZ/XZ = 15/17
3
cos Z = adjacent to ∠Z ÷ hypotenuse = YZ/XZ = 15/17
4
tan X = opposite to ∠X ÷ adjacent to ∠X = YZ/XY = 15/8
sin X = 15/17  |  cos Z = 15/17  |  tan X = 15/8
Example 3 — △PQR, ∠Q = 90°, PQ = 7 cm, QR = 24 cm. Find sin x and cos x (x = ∠P).
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Find hypotenuse PR: PR² = 7² + 24² = 49 + 576 = 625  →  PR = 25 cm
2
Opposite side to ∠P is QR = 24; adjacent side is PQ = 7.
sin x = QR/PR = 24/25  |  cos x = PQ/PR = 7/25
Example 4 — △ABC, ∠C = 90°, BC + CA = 23 cm, BC − CA = 7 cm. Find sin A and tan B.
1
Solve the two equations simultaneously: Adding them gives 2·BC = 30 → BC = 15 cm. Subtracting gives 2·CA = 16 → CA = 8 cm.
2
Find AB using Pythagoras: AB² = 8² + 15² = 64 + 225 = 289  →  AB = 17 cm
3
sin A = opposite/hypotenuse = BC/AB = 15/17;   tan B = opposite/adjacent = AC/BC = 8/15
sin A = 15/17  |  tan B = 8/15

🧠 Important Concept Questions

These questions frequently appear in board exams (CBSE, Telangana, AP) as short-answer or reasoning-type questions:

Does sin x = 4/3 exist for any angle x?

No. Since sin x = opposite ÷ hypotenuse, and the hypotenuse is always the longest side of a right triangle, sin x is always a proper fraction (less than 1). The value 4/3 is greater than 1 — so sin x = 4/3 is impossible.

Why are sin A and cos A always less than 1?

Both sin A and cos A are defined as a ratio where the denominator is the hypotenuse — the longest side. The numerator (opposite or adjacent) is always shorter than the hypotenuse. Therefore the ratio is always a proper fraction, i.e. strictly between 0 and 1.

Is "tan A" a product of "tan" and "A"?

No! In trigonometry, sin, cos, tan etc. are not separate numbers to be multiplied. They are function names — "tan A" means "the tangent of angle A", which equals Opposite ÷ Adjacent. Writing tan × A is meaningless.

Is sin A / cos A equal to tan A?

Yes! Dividing sin A (= Opp/Hyp) by cos A (= Adj/Hyp), the Hyp cancels out and you get Opp/Adj = tan A. Similarly, cos A / sin A = cot A.


🚫 Common Mistakes to Avoid

  • Swapping opposite and adjacent — always identify the angle first, then label the sides relative to that angle.
  • Forgetting to find the third side — most problems require using the Pythagoras theorem before you can compute any ratio.
  • Thinking sin A > 1 is possible — it is not; sin A and cos A are always between 0 and 1 for acute angles.
  • Treating tan as a standalone number — tan A is a single entity representing a ratio, not tan × A.
  • Mixing up reciprocal pairs — cosec is the reciprocal of sin, NOT cos. Remember: co-sine ↔ sec, sine ↔ cosec.

🚀 What This Lesson Prepares You For

The concepts introduced here — the six ratios and how to compute them from a right-angled triangle — are the building blocks for every exercise in this chapter and beyond. Once you are comfortable with this introduction, you are ready for:

  • Exercise 11.1 — Finding trigonometric ratios for given triangles and angles, and verifying reciprocal relationships.
  • Trigonometric Identities — Using sin²A + cos²A = 1 and related identities to simplify and prove expressions.
  • Trigonometric Ratios of Specific Angles — Values of sin 30°, cos 45°, tan 60°, and others that appear repeatedly in board exams.
  • Applications in Heights and Distances, where these ratios are used to find heights of buildings, towers, and distances across rivers.
  • Strengthening your foundation in Similar Triangles, which explains why trigonometric ratios remain constant regardless of triangle size.
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